104
Redistribute to the Right Example
•Censored
observation at 7
–Divide the mass at 7 equally among the remaining subjects
at risk
•Now
mass of 5/28 + 5/56 = 15/56 for each of 9, 10
•Determine
probability of events at next observed (uncensored) event
times
–Pr
(T = 9) = 15/56
–Pr
(T = 10) = 15/56